![]() ![]() Solution: Rearrange the formula to solve for wavelength -Īnd put in the various values, no conversions are needed, though you need to write frequency properly -Įnergy of a photon - There are two versions of this formula, one using the frequency, the other using the wavelength. If a particular type of light has a frequency of 1 million /second, what is its wavelength? If a particular type of light has a wavelength of 6430 Å, what is its frequency? Mathematically this would be written asĪnd the 10s cancel out. So for the left side to stay the same while becomes 10 times larger, f must become 10 times smaller. Solution: Since the speed of light (c) cant change, when you change one part of the formula, the other part mush ![]() If a light's wavelength is increased by a factor of 10, how does its frequency change? So if the wavelength goes down the frequency goes up, and vice versa.ġ. That means if you change something on the right side (either the wavelength or the frequency) then the other thing has to also change, but in the opposite sense. So the left side of the formula always has the same value. This is a very important relationship since it tells you several things - first of all, the speed of light is constant - it never changes (as far as we're concerned in this class). f = the frequency at which light waves pass by, measured in units of per seconds (1/s).= the wavelength of light, usually measured in meters or Ångströms (1 Å = 10 -10 m).c = the speed of light = 300,000 km/s or 3.0 x 10 8 m/s. ![]() A fairly simple, but important relationship. Light Properties - shows the relationship between the speed of light, its wavelength and its frequency. ![]()
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